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-.1x^2+143x-2850=0
We add all the numbers together, and all the variables
-0.1x^2+143x-2850=0
a = -0.1; b = 143; c = -2850;
Δ = b2-4ac
Δ = 1432-4·(-0.1)·(-2850)
Δ = 19309
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(143)-\sqrt{19309}}{2*-0.1}=\frac{-143-\sqrt{19309}}{-0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(143)+\sqrt{19309}}{2*-0.1}=\frac{-143+\sqrt{19309}}{-0.2} $
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